Is moderated livestock grazing an effective countermeasure for desertification? Should I remove older low level jobs/education from my CV at this point? So, here is the working solution. To learn more, see our tips on writing great answers. Here in this word, s at the beginning of the word, the output has to be sWordbreakproblem Site design / logo 2022 Stack Exchange Inc; user contributions licensed under CC BY-SA. For example you could try to call your loop again from the second character onwards if no matches are found in the initial loop and so on. Check if a given key already exists in a dictionary, How to upgrade all Python packages with pip. And, also. How can I make a dictionary from separate lists of keys and values? I didn't even notice that 'hllo' in there. Because of that, 'sWordbreakproblem' is still not segmentable with that dictionary of words. In your loop, you will check if 'a', 'ab', 'abc', 'abcd', 'abcde' are in the dictionary. Corrected that now. I am trying to solve the word break problem. Also modified the question. I understood the method suggested. Ah ok sorry I missunderstood your question. But unfortunately the word in the question described was mistaken. Why do the displayed ticks from a Plot of a function not match the ones extracted through Charting`FindTicks in this case? The word is Wordbreakproblems or sWordbreakproblem or Wordbreakproblem. @imhans4305 the solution should work with any word. Making statements based on opinion; back them up with references or personal experience. hackerearth Let's consider the word 'abcde'. How do I sort a list of dictionaries by a value of the dictionary? @Pychopath Given an input string and a dictionary of words, this has to find out if the input string can be segmented into a space-separated sequence of dictionary words. Can a human colony be self-sustaining without sunlight using mushrooms? At least, this solution does the following job: it break the given word in all the possible way with words of the dictionary, except for the last word which may not belong to the dictionary, if it is does not start itself with a word of the dictionary. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. It can still be solved in linear time, but using automata theory. and if s is at the end of the word then the output has to be like, If s is at the middle of the word like Wordbreaksproblem. Then your empty output is correct. You will have to change/modify your approach. How would electric weapons used by mermaids function, if feasible? However, luckily enough, automata theory translates very well to regular expressions (even though Python's implementation is not based on automata theory, and therefore slower): This has a linear complexity (contrary to the other approaches considered so far in this post). Blondie's Heart of Glass shimmering cascade effect. Trending is based off of the highest score sort and falls back to it if no posts are trending. How can I remove a key from a Python dictionary? Find centralized, trusted content and collaborate around the technologies you use most. 465), Design patterns for asynchronous API communication. Perfectly forwarding lambda capture in C++20 (or newer). I'll give the code for that soon :D, I dont want all the splits. merge Asking for help, clarification, or responding to other answers. Can anyone Identify the make, model and year of this car? But some input cases are not giving result. Getting key with maximum value in dictionary? rev2022.7.21.42639. It does work for all the examples you've given. Can you upvote the question too. Thankyou. I had completely missed the point of the original question. Your really want all possible outputs? I'm talking about that 's' at the start. Then only the bruteforce way works I fear. What you want to do is considerably harder than the original word break problem. And you're still showing multiple segmentations instead of one boolean value. If there are no words starting with 'a' in your dictionary, then nothing happens in your loop. I am looking for solutions which match with that in list and not matching also. ali Also, not clear why you show several segmentations if the job is to just find out, @Pychopath There was a mistake in the example word given. You can now choose to sort by Trending, which boosts votes that have happened recently, helping to surface more up-to-date answers. Why is the US residential model untouchable and unquestionable? There is a problem with your approach. Can you upvote the question ? Connect and share knowledge within a single location that is structured and easy to search. Announcing the Stacks Editor Beta release! Sum of Convergent Series for Problem Like Schrdingers Cat. Thanks for the solution provided. Thanks for contributing an answer to Stack Overflow! Because 'sWordhllobreakproblem' can't be segmented like that. Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. Why dont second unit directors tend to become full-fledged directors? Scientific writing: attributing actions to inanimate objects. In the US, how do we make tax withholding less if we lost our job for a few months? Apologizing for that. Word Break Problem with no matching word in Dictionary, How APIs can take the pain out of legacy system headaches (Ep. If word = 'sWordbreakproblem', then the code is not giving any output. 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